19.3 mL of a solution of KMnO4 is required to completely oxidize 1.89 g of Mo2O3 to MoO4-2. What is the molarity of the KMnO4 solution? 3MnO4-1 + 5Mo+3 + 8H2O —-> 3Mn+2 + 5MoO4-2 + 16H+1 Please explain how to do it. I already have the answer (0.490 M KMnO4). Was this Helpful?