i solved it like this:

log n^n = 1000

2^1000 = n^n

1000 ln 2 = n ln n < stuck here 🙁

Comments on "How to solve: (n log n = 1000) where log is base 2?"

i solved it like this:

log n^n = 1000

2^1000 = n^n

1000 ln 2 = n ln n < stuck here 🙁

Comments on "How to solve: (n log n = 1000) where log is base 2?"