A rocket starts from rest and moves upward from the surface of the earth. For the first 10.0 s of its motion, the vertical acceleration of the rocket is given by ay=(2.90m/s3)t, where the +y-direction is upward.

Part A

What is the height of the rocket above the surface of the earth at t = 10.0 s ?

Express your answer with the appropriate units.

Part B

What is the speed of the rocket when it is 265 m above the surface of the earth?

Express your answer with the appropriate units.